8m^2=104

Solution for 8m^2=104 equation:

8m^2=104

We move all terms to the left:

8m^2-(104)=0

a = 8; b = 0; c = -104;
Δ = b2-4ac
Δ = 02-4·8·(-104)
Δ = 3328
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3328}=\sqrt{256*13}=\sqrt{256}*\sqrt{13}=16\sqrt{13}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-16\sqrt{13}}{2*8}=\frac{0-16\sqrt{13}}{16}
=-\frac{16\sqrt{13}}{16}
=-\sqrt{13}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+16\sqrt{13}}{2*8}=\frac{0+16\sqrt{13}}{16}
=\frac{16\sqrt{13}}{16}
=\sqrt{13}
$